Answer:
The minimum distance has to be 15ft
Explanation:
Since car A is behind, I am fixing the origin in that point.
Now, let's calculate the position, for both cars at the end of everything, measured from the origin.
I am using this formula for
For car A:
And we also know that , So:
For car B:
Replacing the values we get:
To avoid a collision, , so:
165 ≤ d + 150 If we solve for d: d ≥ 15ft
Answer:
It was created during the French Revolution in 1799 and has enabled for the international exchange of scientific and technical information. Calculating with SI units is also a lot easier than using the English system.
Dont where socks or stand on carpet while working on a computer, also dont set components on carpet.
Answer:
F = -6472.9 N
F= -6.47 kN
Explanation:
First of all you have to convert the data to SI units
so for the velocity you have :
Vi = 43km/h *(1000m/1km)*(1h/3600s) ---> using conversion factors
Vi= 11.9444 m/s
dX : distance the passanger moves
dX = 54cm*(1m/100cm) --> using conversion factors
dX = 0.54 m
Now to calculate the force we are going to use the sum of focers equals to mass for acceleration:
Sum F = m*a
We have to find a so we are going to use the velocity's formula as follows to solve a:
Vf ^2 = Vi^2 +2*a*dX
Vf=0 --> the passenger does not move after the airbag inflates.
a= -(Vi^2)/(2*dX)
you solve de acceleration with the data you hae and you will find
a = -132.1 m/ s^2
Now you can solve the Sum F equation
Sum F = 49 Kg * (-132.1 m/s^2)
F = -6472.9 N
F= -6.47 kN
Answer:
20 m/s
Explanation:
The force experienced by a charged particle in an electric field is given by
where, in this problem:
is the charge of the particle
E is the electric field
The electric field here has components:
So the components of the force experienced by the particle are:
Now we can find the components of the acceleration experienced by the particle, using Newton's second law of motion:
where
m = 4.0 g = 0.004 kg is the mass of the particle
The 3 components of the acceleration are:
Now we can find the components of the velocity of the particle at time t using the suvat equation:
where:
are the initial components of the velocity
Therefore, at t = 2.0 s, we have:
And so, the speed of the particle is the magnitude of the final velocity: