Answer:
54mph
Explanation:
Speed is defined as the change in distance of a body with respect to time.
Let x be the speed of Eric on his way to the football game, if he used 11hours to the football game, his distance will be the product of his speed and time taken i.e
Distance = speed × time
Distance= x × 11
Distance = 11x... (1)
During his return journey, his speed increases by 12mph with a return drive in only 9hours i.e speed = x+12 and time is 9hours
Since distance = speed × time (return Journey)
Distance = (x+12)×9
Distance = 9x+84...(2)
Note that the distance to and fro the journey is the same as such we will equate equations 1 and 2 to get his initial speed "x" to have;
11x = 9x+84
11x-9x = 84
2x = 84
x = 42mph
This means that his initial speed on his way to the football game is 42mph. Since his speed increases by 12mph during his return drive, his return speed will be 42mph + 12mph which gives 54mph.
Answer:
See explanation below.
Explanation:
For this case we atart fom the proportional model given by the following differential equation:
And if we rewrite this expression we got:
If we integrate both sides we got:
And using exponential on both sides we got:
Where represent the initial amount for the isotope and t the time in years and A the amount remaining.
If we want to apply a model for the half life we know that after some time definfd the amount remaining is the hal, so if we apply this we got:
We can cancel and we got:
If we solve for k we can apply natural log on both sides and we got:
And that would be our proportional constant on this case.
If we replace this value for k int our model we will see that:
And using properties of logs we can rewrite this like that:
And thats the common formula used for the helf life time.
Answer:
c. 20 amps.
just divide the watts by the volts
Answer:
λ = 5.656 x 10⁻⁷ m = 565.6 nm
Explanation:
Using the formula of fringe spacing from the Young's Double Slit experiment, which is given as follows:
where,
λ = wavelength = ?
Δx = fringe spacing = 1.6 cm = 0.016 m
L = Distance between slits and screen = 4.95 m
d = slit separation = 0.175 mm = 0.000175 m
Therefore,
<u>λ = 5.656 x 10⁻⁷ m = 565.6 nm</u>