Answer:
y = 2(x+5)²- 60
Step-by-step explanation:
f(x) = ax² +bx +c, is the standard form
f(x) = a(x - h)² +k , is the vertex form where the (h, k) is the vertex
y = 2x²+20x -10 ,
factor 2 from the two terms
y = 2(x² +10x) -10,
what perfect square has x² +10x? ... x²+10x +25 = (x+5)²
y = 2(x²+10x+25 )- 50 -10,
add 25 in parenthesis to get a perfect square yet subtract 2*25 = 50 so the equation will stay the same
y = 2(x+5)²- 60,
the equation has the vertex at (-5, -60)
{(9)(9/256)}^3/2=
(81/256)^3/2=
0.031676352/2=
0.015838176
79/10 = 7.9 hope it helps
F(x) = x^2 -2x + 4
f(-2) = (-2)^2 -2(-2) +4
f(-2) = 4 + 4 + 4
f(-2) = 12
12 is your answer
Hope this helps
