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3 years ago

HELP PLS FIRST RIGHT ANSWER BRAINLIEST

Mathematics

1 answer:

8090 [49]3 years ago

4 0

Answer: A

Step-by-step explanation: it has to be a low number and that’s a low number.

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In the image shown, line n is a transversal cutting parallel lines l and m. ∠1 = 3x + 18 ∠7 = 2x + 39 What is the measure of ∠7?

wel

Answer:

B) 81°

Step-by-step explanation:

Given:

From the figure given below,

∠1 = 3x + 18

∠7 = 2x + 39

∠1 and ∠7 are a pair of exterior alternate angles. For two parallel lines l and m, cut by a transversal n, the pair of exterior alternate angles are congruent to each other.

Therefore, the angles 1 and 7 are congruent to each other. This gives,

∠1 ≅ ∠7

$3x+18=2x+39\\\\3x-2x=39-18\\\\x=21$

Therefore, the value of 'x' is 21.

Now, the measure of angle 7 can be calculated by plugging in the value of 'x' in the expression for angle 7. This gives,

$\angle 7 = 2x + 39\\\\\angle 7 =2\times 21+39\\\\\angle 7 =42+29\\\\\angle 7 =81\°$

Therefore, the correct option is option (B).

4 0

4 years ago

Read 2 more answers

Write the pair of fractions as a pair of fractions with a common denominator 2/4 and 5/8

Nostrana [21]

4/8 and 5/8

The two denominators have a least common multiple of 8.

So 2/4 would turn into 4/8.

The second fraction is over 8, so you don’t need to change that one.

5 0

3 years ago

Need It Fast please! =)

Mashcka [7]

Answer:

split the other three in half

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Ayla is buying fence for two triangular sections of her garden. How much fence would she need for ΔDFG?

zysi [14]

Answer:

80 ft

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Hello i need help on these two questions thank you

Evgen [1.6K]

Answer:

Question 5. $a=2$

Question 6. $d=4$

Step-by-step explanation:

Question 5.

Given:

$\frac{3^{a}2\sqrt{9}}{27\sqrt{4}} = 1$

Solution:

$\frac{3^{a}2\sqrt{9}}{27\sqrt{4}} = 1$

$3^{a} 2\sqrt{9} =27\sqrt{4}$

$3^{a} =\frac{27\sqrt{4} }{2\sqrt{9} }$

$3^{a}=\frac{27\sqrt{2^{2} } }{2\sqrt{3^{2} } }$

$3^{a}=\frac{27\times 2}{2\times 3}$

$3^{a}=\frac{27}{3}$

$3^{a}=9$

$3^{a}=3^{2}$

Take log both side.

$log(3)^{a} =log(3)^{2}$

Simplify th above equation.

$a\times log(3)=2\times log(3)$

log(3) cancelled both side

$a=2$

Question 6.

Given:

$\frac{3^{d}\sqrt{5}}{3^{2}\sqrt{45}} = 3$

Solution:

$\frac{3^{d}\sqrt{5}}{3^{2}\sqrt{45}} = 3$

$3^{d}\sqrt{5} =3\times 9\sqrt{45}$

$3^{d} =\frac{27\sqrt{45} }{\sqrt{5} }$

$3^{d} =27\sqrt{\frac{45}{5}}$

$3^{d} =27\times \sqrt{9}$

$3^{d} =27\times \sqrt{3^{2}}$

$3^{d} =27\times 3$

$3^{d} =81$

$3^{d}=3^{4}$

Take log both side.

$log(3)^{d} =log(3)^{4}$

Simplify the above equation.

$d\times log(3)=4\times log(3)$

log(3) cancelled both side

$d=4$

Therefore $a=2$ for question 5 and $d=4$ for question 6.

4 0

3 years ago