2.350 × 10‐⁴ Write each number in standard notation.

Mathematics

2 answers:

krok68 [10]3 years ago

8 0

I couldn't tell from your question if there was a negative on the 4 or not.

If your number was $2.350 \times 10^{4}$ , you're being told to make the number bigger by moving the decimal point 4 places to the right. You essentially multiplying by 10 four times over.

If your number was $2.350 \times 10^{-4}$ , you're being told to make the number smaller by moving the decimal point 4 places to the left You essentially dividing by 10 four times over.

Can you take it from there?

storchak [24]3 years ago

7 0

Answer: 0.00235 is ur answer

Step-by-step explanation://Give thanks(and or Brainliest) if helpful (≧▽≦)//

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36.

Burka [1]

Area 1st rectangle = 10 * 7 = 70 cm^2
length of 2nd rectangle is 2*7 = 14 cm

Area 2nd = 10 * 14 = 140 cm^2

140/70 = 2

The 2nd triangle was twice as big as the 1st. Answer A

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4 years ago

The diameter of a circle has endpoints (-10,5) and (-4,11)

Marta_Voda [28]

well, since we know the endpoints for the diameter, its midpoint will be where the center of the circle is located, so

$~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{11}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ -4 -10}{2}~~~ ,~~~ \cfrac{ 11 + 5}{2} \right)\implies \left(\cfrac{-14}{2}~~,~~\cfrac{16}{2} \right)\implies \stackrel{center}{(-7~~,~~8)}$

and if we get the distance between those endpoints, and take half of that, that'd be the radius of it.

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{11})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-4 - (-10)]^2 + [11 - 5]^2}\implies d=\sqrt{(-4+10)^2+6^2} \\\\\\ d=\sqrt{6^2+6^2}\implies d=\sqrt{72}~\hfill \stackrel{radius=half~that}{\cfrac{\sqrt{72}}{2}} \\\\[-0.35em] ~\dotfill$

$\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-7}{ h},\stackrel{8}{ k})\qquad \qquad radius=\stackrel{\frac{\sqrt{72}}{2}}{ r} \\\\\\\ [x-(-7)]^2~~ + ~~[y-8]^2~~ = ~~\left( \frac{\sqrt{72}}{2} \right)^2\implies (x+7)^2~~ + ~~(y-8)^2~~ = ~~18$

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2 years ago

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miskamm [114]

Answer:

Step-by-step explanation:

A good trick for trigonometric functions is to remember SOHCAHTOA:

Sin=Opposite over Hypotenuse

Cos=Adjacent over Hypotenuse

Tan=Opposite over Adjacent

The red arrows on the attachment indicate where opposite, hypotenuse, and adjacent are for angle A.

So in this case, the sin of angle A (opposite over hypotenuse) would be $\frac{24}{26}$ and cos A (adjacent over hypotenuse) would be $\frac{10}{26}$ .