<span>they appear to be using the (2x) as the variable;
so,
</span><span>e^(t) + t^2 ;
now fill in the interval [0,2x]
e^(2x) + (2x)^2 -e^(0)
D{t} [e(2x) +4x^2 - 1]
2e^(2x) + 8x</span>
18.5-0.5= 18
18/3= 6
So r=6
Answer:
p=7
∠BRG=49
Step-by-step explanation:
∠BRG and ∠YRG are on a straight line together. Therefore, they are supplementary and add to 180 degrees.
∠BRG+∠YRG=180
We know that ∠BRG is 7p and ∠YRG is 131 degrees. Substitute 7p in for ∠BRG and 131 for ∠YRG.
7p+131=180
We want to find out what p is. In order to do that, we have to get p by itself. First, subtract 131 from both sides.
7p+131-131=180-131
7p=49
Next, divide both sides by 7.
7p/7=49/7
p=49/7
p=7
Now, we have to find what ∠BRG is.
∠BRG=7p
We know that p=7, so substitute p in for 7
∠BRG=7*7
∠BRG=49
So, p=7 and ∠BRG=49
