Find the exact value using trigonometric identities
840, 79
so to find the slope we do y2- y1/ x2-x1
plug in the coordinates: (-6,4) (0,3)
3-4/ 0--6
3-4/0+6
= -1/6
Then using the formula of slop intercept form: y=mx+b........ use one of the coordinates to plug in
4= -1/6x+b...... multiply -6/1 on both sides of equation ( you do this so -1/6 and -6/1 can cancel out)
-24=b........ Use b to plug in y=mx+b---------> y= -1/6x-24
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
50 cents beacuse in 1970 it cost 50 cents in 1980 it cost 1.00