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NeX [460]
3 years ago
5

GIVING 50 POINTS Find the missing length indicated. Pls show your work

Mathematics
2 answers:
KengaRu [80]3 years ago
7 0
  • 24-9=15

\\ \sf\longmapsto \dfrac{20}{3x-18}=\dfrac{15}{9}

\\ \sf\longmapsto 300=15(3x-18)

\\ \sf\longmapsto 300=45x-270

\\ \sf\longmapsto 45x=570

\\ \sf\longmapsto x\approx 13

cluponka [151]3 years ago
5 0

Answer:

• from scale factors, big triangle : small triangle

\dashrightarrow \: { \tt{ \frac{24}{(24 - 9)} =  \frac{(3x - 18) + 20}{20}  }} \\  \\\dashrightarrow \:  { \tt{20 \times 24 = (3x + 2) \times 15}} \\  \\  \dashrightarrow \: { \tt{480 = 45x + 30}} \\  \\ \dashrightarrow \: { \tt{45x = 450}} \\  \\ \dashrightarrow \: { \boxed{ \tt{x = 10}}}

• The missing length:

= { \tt{3x - 18}} \\  \\  = { \tt{3(10) - 18}} \\  \\  = { \tt{30 - 18}} \\  \\ \dashrightarrow \: { \boxed{ \boxed{ \tt{ \:  \: missing \: length = 12 \:  \: }}}}

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State the equation of the line which has the y-intercept :
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Drag the tiles to the correct boxes to complete the pairs. Find the distance between each pair of points. 5 units 4 units 2 unit
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a) Distance between points A (5, 4) and B( 5, -2) is 6 units

b) Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) Distance between points G(3, -5) and H(6, -5) is 3 units

Step-by-step explanation:

We need to find the distance between each pair

a) A (5, 4) and B( 5, -2)

the distance formula is:

d(A,B) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Putting values: x₁ = 5, x₂=5 and y₁= 4 and y₂= -2

d(A,B) = \sqrt{(5-5)^2+(-2-4)^2}

d(A,B) = \sqrt{(0)^2+(-6)^2}

d(A,B) = \sqrt{36}

d(A,B) = 6

Distance between points A (5, 4) and B( 5, -2) is 6 units

b)  E (-2, -1) and F( -2, -5)

the distance formula is:

d(E,F) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Putting values: x₁ = -2, x₂=-2 and y₁= -1 and y₂= -5

d(E,F) = \sqrt{(-2-(-2))^2+(-5-(-1))^2}

d(E,F) = \sqrt{(0)^2+(-4)^2}

d(E,F) = \sqrt{16}

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Distance between points E (-2, -1) and F( -2, -5) is 4 units

c)  C (-4, 1) and D( 1, 1)

the distance formula is:

d(C,D) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Putting values: x₁ = -4, x₂=1 and y₁= 1 and y₂= 1

d(C,D)= \sqrt{(1-(-4))^2+(1-(1))^2}

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Putting values: x₁ = 3, x₂=6 and y₁= -5 and y₂= -5

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3 years ago
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