Answer: 0.335 moles
Explanation:
Given that,
Amount of moles of KBr solute (n) = ?
Volume of KBr solution (v) = 0.67 L
Concentration of KBr solution (c) = 0.50M
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
make n the subject formula
n = c x v
n = 0.50M x 0.67L
n = 0.335 moles
Thus, there are 0.335 moles of KBr in 0.67 L of a 0.50 M KBr solution
The way to start it is simply by converting 0.239 L of dinitrogen oxide gas into moles of gas using the ideal gas equation
at STP , 1 mol of gas is 22.4 L of gas, or you could simply use pv = nRT
hope this helps
Answer:
B
Explanation:
follow the chart starting at the y axis go away from it at the level of 1 till you hit 100
1.<span>olution is an acid. When </span>hydrogen<span> chloride is </span>dissolved in water, the solution iscalled<span> hydrochloric acid. substances, so the solution is a base. ... When a proton—a</span>hydrogen ion<span>—from an acid is accepted by a hydroxide </span>ion<span> from a base, the two </span>ions<span>join together and </span>form<span> a molecule of </span>water<span>.
2.</span><span>The strong acid </span>hydrogen<span> chloride (HCl) is one example. If one of the </span>ions<span> is </span>OH-, thesolution<span> is basic. An example of a strong base is sodium hydroxide (NaOH). There are other </span>ions<span> that make acidic and basic </span>solutions<span>, but we won't be talking about them here.
3.</span>If one of those ions is H+<span>, the solution is acidic. The strong </span>acid<span> hydrogen chloride (HCl) is one example. If one of the ions is </span>OH-<span>, the solution is basic. An example of a strong base is sodium hydroxide (NaOH).
4.</span><span>The strong acid hydrogen chloride (HCl) is one example. If one of the </span>ions<span> is </span>OH-, thesolution<span> is basic. An example of a strong base is sodium hydroxide (NaOH). There are other </span>ions<span> that make acidic and basic </span>solutions<span>, but we won't be talking about them here.</span>