Tan3A=tan(2A+A)
We know that , tan(x+y)=(tanx + tany)/(1 - (tanx)(tany))
tan(2A+A)=(tan2A+tanA)/(1 - (tan2A)(tanA))— (1)
We know that , tan2x=2tanx/(1 - tan^2x)
So, by substituting tan2A in (1),we get,
=[2tanA/(1 - tan^2A) + tanA]/1- (2tanA/(1 - tan^2A))(tanA)]
=[2tanA+tanA - tan^3A]/[1 - tan^2A - 2tan^2A]
=[3tanA - tan^3A]/[1-3tan^2A]
Therefore, tan3A= [3tanA - tan^3A]/[1-3tan^2A]
Answer:
Brroooommm.
Step-by-step explanation:
Bleee Puro ka brainly magaral ka Naman nga buti
Given that the angles of the two sectors are equal, we can find the relationship between the angles, radii, and the lengths of the arc
The length of the arc (S) is given by the formula
Then we can make the angle the subject of the formula
For the first sector
For the second sector
Simplifying the equation, we will obtain
Answer: 51°F
Step-by-step explanation:
72 - 21 = 51
Step-by-step explanation:
Hey there!
The given slope is; 3. And passing through point (-7,8).
Now,
Using one point formula.
Put all values to find equation.
Simplify them to get answer.
Therefore the required equation is 3x-y+29=0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>