What is the equation of the line that passes through the point (2, 1) and has a
slope of 3/2?
2 answers:
Answer:
Step-by-step explanation:
Use the form y = mx + b and plug in your known point
y = 3x/2 + b
1 = 3(2)/2 + b
1 = 3 + b
b = -2
y = 3x/2 - 2
we can use a plotting calculator to verify our result.
<u>Given </u><u>:</u><u>-</u>
- A line having a slope of 3/2 passes through (2,1) .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- The equation of the line .
<u>Answer </u><u>:</u><u>-</u>
According to the question ,
We know <u>Point</u><u> slope</u><u> form</u><u> </u> of the line as ,
Substitute ,
- y - 1 = 3/2 ( x - 2 )
- y - 1 = 3/2x - 3/2*2
- y - 1 = 3/2x - 3
- 2( y -1) = 3/2x *2 - 3*2
- 2y - 2 = 3x - 6
- 3x - 2y -4 = 0
<u>Hence</u><u> the</u><u> </u><u>equation</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>3</u><u>x</u><u> </u><u>-2y</u><u>-</u><u>4</u><u>=</u><u>0</u><u> </u><u>.</u>
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