While I'm unsure what the word choices were, his claim is likely to be true.
Since he claims the probability of heads is 40%, that should be what we see in an experiment. 0.38 is very close to 0.40, or 40%, so this is true. Therefore his claim is likely to be true, and the probability of tails should be about 60%.
The correct answer is b as she starts with 10 and keeps on added 3 dollars per week
To solve this, we use the formula for the volume of the frustum of a cone which is expressed as:
<span>V= (H/6)[WL + (W+a)(L+b) + ab]
</span>V = 3/6 [(6 ft. × 8 ft.) + (6 + 14)(18 + 8) + (<span>14 ft. × 18 ft.)]
</span>V = 409.98 ft^3 <-----OPTION C
To get the probability of two individual events both occurring,
you have to multiply the probabilities of their individual events occurring. Therefore
in this problem, the probability that a student selected at random will pass
both French 101 and French 102 is 0.683 (.75 x .91). The answer is already
rounded to three decimal places.
