Answer:
The strength of an electric field as created by source charge Q is inversely related to square of the distance from the source. This is known as an inverse square law. Electric field strength is location dependent, and its magnitude decreases as the distance from a location to the source increases.
Explanation:
Answer:
Technician A only
Explanation:
Both high-side pressures and low-side pressures are low with the engine running and the selector set to the air-conditioning position. Technician A says that the system is undercharged. Technician B says the cooling fan could be inoperative. Which technician is correct?
usually . An overcharged system will result in lower than normal low side pressures
An undercharged system will not enable the compressor to create pressure. As a result of the low amount of refrigerant, the cooling ability is reduced. When we say undercharged, we mean the refrigerant in the system is low, so the both the high side pressures and low side pressures will be low.
1) You can find the velocity with which the jumper leaves the ground by using the formula for the final velocity of an upward vertical motion.
Vf^2 = Vo^2 - 2gd
The data known are: Vf = 0, g = 9.81 m/s^2, and d = 60 cm = 0.6 m
=> Vo^2 = 2gd = 2*9.81m/s^2 * 0.6 m = .11.772 m^2/s^2 =>
Vo = 3.4 m/s
2) You can obtain the acceleration of the jumper during the jump by using the equivalent formula, Vf^2 = Vo^2 + 2ad
Where, Vf^2 is the velocity with which he leaves the ground (3.4 m/s), Vo is zero because he jumps from the rest, d is the distance that his body rises from knees,which is 50 cm = 0.5 m
Then, a = Vf^2 / 2d = [3.4m/s]^2 / (2*0.5m) = 11.6 m/s^2
And now, you can find the force exerted by the jumper as:
F = m*a, and if you know his weight, W = m*g => m = W/g
Replace m in F = m*a => F = W*a/g = W*11.6m/s^2 / 9.81 m/s^2 = 0.10 W
F = 0.10 W