Which of the functions below could have created this graph

Mathematics

1 answer:

abruzzese [7]3 years ago

5 0

Answer:

the answer is

Step-by-step explanation:

I think the answer is C

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What is the surface area of cone below Diameter AB=21 and distance from B to C =36

Vesnalui [34]

Answer:

1533.88261311522

Step-by-step explanation:

Let r be the radius of the (base/circle)

and L be the slant height of the cone

Formula ………………………………………………………………………………………………………

The surface area of a cone = the (curved/lateral) surface area + the base

$=\pi r^{2}\ \ \ +\ \ \ \pi Lr$

=========================================

$r=\frac{21}{2} =10.5$

L = BC = 36

$\text{surface area} =\pi \left( 10.5\right)^{2} +\pi \times 36\times \left( 10.5\right)$

$=346.360590058275 + 1187.52202305694$

$=1533.88261311522$

6 0

2 years ago

3√x -2/x^2 please show step by step of differentiation before combining the terms.

EastWind [94]

Answer:

Step-by-step explanation:

Before we differentiate, let us assign a variable to the function. Let y be equal to the function i.e let y = 3√x -2/x²

In differentiation if $y = ax^{n}$ , then $\frac{dy}{dx} = nax^{n-1}$ where n is a constant and dy/dx means we are differentiating the function y with respect to x.

Applying the formula o the question given;

$y= 3\sqrt{x} -2/x^2\\y = 3{x}^\frac{1}{2} - 2x^{-2} \\\\$

On differentiating the resulting function;

$\frac{dy}{dx} = \frac{1}{2}*3x^{\frac{1}{2}-1 } - (-2)x^{-2-1} \\\\\frac{dy}{dx} = \frac{1}{2}*3x^{-\frac{1}{2}} + 2x^{-3}\\ \\\frac{dy}{dx} = \frac{1}{2}*{\frac{3}{x^{\frac{1}{2} } }} + \frac{2}{x^{3} } \\\\\frac{dy}{dx} = {\frac{3}{2x^{\frac{1}{2} } }} + \frac{2}{x^{3} }\\\\\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }$