JIG is clockwise around the figure, as is DEF, so there is no reflection involved. The midpoint between any two corresponding vertices is (1, 4), so that is the center of rotation. Figure DEF is "upside down" from JIG, so rotation is 180°.
The 1st selection is appropriate.
Answer:
±10i
Step-by-step explanation:
sqrt( -100)
sqrt( 100*-1 )
We know sqrt(ab) = sqrt(a) sqrt(b)
sqrt(100)sqrt(-1)
We know that sqrt(-1) = i
±10i
Y=16+0.5x
To find the order pairs of the given function, put value of x and get the value of y.
When x=0
y=16+0.5(0)
y=16+0
y=16
Ordered pair is (0,16)
When x =2
y=16+0.5(2)
y=16+1
y=17
Ordered pair is (2,17)
When x=-2
y=16+0.5(-2)
y=16-1
y=15
Ordered pair is (-2,15)
So table for the given function is:
x | y
0 | 16
2 | 17
-2 | 15
Just put value of x in the given function and get y.
The Jacobian has determinant
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