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3 years ago

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2. All objects contain both what and what charges.

1 answer:

sattari [20]3 years ago

6 0

Answer:

All objects are composed of these atoms. ... Charged objects have an imbalance of charge - either more negative electrons than positive protons or vice versa. And neutral objects have a balance of charge - equal numbers of protons and electrons.

Explanation:

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A.to reduce<br> b.to dispose<br> c.to prevent<br> d.to help

kenny6666 [7]

Answer:

to prevent cuz now for my mind when you prevent it it will not happen to you or nothing happened to you

5 0

3 years ago

Elle is pushing a box of mass 7.0 kilograms with the force of 25 newtons. If the force of friction is 2.6 newtons, what is the v

BigorU [14]

In the given question, there are several information's of immense importance. Using those given information's, it is easy to get to the required result. It is given that the mass of the box Ellie is pushing is 7 kg with a force of 25 newtons. the force of friction effecting the acceleration is 2.6 Newton.
We already know that
Force = mass * Acceleration
We also know that
Force = Force applied - Force of friction
   = (25 - 2.6) Newton
   = 22.4 Newton.
Now putting the value of force in the equation, we get
Force = Mass * Acceleration
22.4 = 7 * Acceleration.
Acceleration = 22.4/7
   = 3.2 m/s^2
So the value of acceleration is 3.2 m/s^2

3 0

3 years ago

I'm so tired of these useless answers and bots, someone please help me.

Anestetic [448]

Answer:

The kite string is $55$ feet long.

Explanation:

Use the Pythagorean Theorem, which is $a^2 + b^2 = c^2$ .

Here the question is asking for $c$ , which would be the hypotenuse, or the longest side of the triangle.

So the $a$ would be $20 + 13$ , and the $b$ would be $44$ .

Plug those values into the formula, and that would get $33^2 + 44^2 = c^2$ .

Now, solve for $33^2 + 44^2$ , which would equal $3025$ .

That means we would have to solve for $3025 = c^2$ .

Square root both sides of the equation, getting $c = \sqrt{3025}$ .

Solve for $\sqrt{3025}$ , which would get us $55$ .

Hence, the answer to this would question would be $55$ .

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

6 0

3 years ago

Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin

Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

$\mu_o=4\pi \times 10^{-7}\ T-m/A$

Resistivity, $\rho=1.72\times 10^{-8}\ \Omega-m$

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

$R=\rho \dfrac{l}{A}$

$R=\rho \dfrac{l}{\pi r^2}$

$r=\sqrt{\dfrac{\rho l}{R\pi}}$

$r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}$

r = 0.00199 m

or

$r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m$

The magnetic field on a current carrying wire is given by :

$B=\dfrac{\mu_o I}{2\pi r}$

$I=\dfrac{2\pi rB}{\mu_o}$

$I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}$

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0

3 years ago

Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley

kondaur [170]

Answer:

IDK

Explanation:

IDK

4 0

3 years ago

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