Answer:
- cylinder — 90π in³
- pyramid — 37 1/3 in³
- cone — 12.5π in³
Step-by-step explanation:
The volume of a cylinder is given by ...
V = Bh . . . . . where B is the base area and h is the height
The volume of a pyramid or cone is given by ...
V = (1/3)Bh . . . . . where B is the base area and h is the height
The area of a square of side length s is ...
A = s²
The area of a circle of radius r is ...
A = πr²
___
Using these formulas, the volumes of these objects are ...
cylinder: (9π in²)(10 in) = 90π in³
square pyramid: (1/3)(4 in)²(7 in) = 37 1/3 in³
cone: (1/3)(π(2.5 in)²)(6 in) = 12.5π in³ . . . . slightly larger than the pyramid
Answer:
517
Step-by-step explanation:
The radius of a circle is just half of the diameter (1/2d = r)
1034/2 = 517
Answer:
-36,047.
Step-by-step explanation:
Sum of n terms = a1 .( r^n - 1) / (r - 1)
So Sum of 7 terms = -11 . ((-4)^7 - 1 / (-4-1)
= -11 * -16,385 / -5
= -36,047.
You can find the value of p by dividing both sides of the equation by 2. Resulting in 3.5 as the answer
Answer:
B
Step-by-step explanation:
There isn't any number that x can't be. Start with a graph to show how this could be so.
It is easy to see that x > 0 gives a line that goes very near the x axis. It is not quite so easy to see that it never touches the x axis. But if you recreate the graph in Desmos, you will see that is true if you spread the x's out.
It is not quite so easy to see that when x<0 the graph tips upward very quickly but again if you move the values of the axis around you will see there is no value that x cannot be.
