Answer:
x^3 - 1
Step-by-step explanation:
(x^2 + x + 1) (x - 1)
Here we have to use the distributive property.
(x^2 + x + 1)x -1(x^2 + x + 1)
Now distribute x and -1 inside the parenthesis, we get
x^3 + x^2 + x -x^2 - x - 1
Now we have to simplify the like terms.
x^3 + x^2 -x^2 + x - x -1 [x^2 - x^2 =0; x -x = 0]
= x^3 - 1
The answer is x^3 - 1
Thank you.
Answer:
28
Step-by-step explanation:
4: 4, 8, 12, 16, 20, 24, 28
7: 7, 14, 21, 28
Answer:
Simple linear equation is :
Y = 86.784 - 2.67x
Step-by-step explanation:
The educator wants to see the relationship between no of absences and final grades of the student. No. of absence of student is independent variable while final grade is dependent variable. The final grades of the student are dependent on the no. of absence they do.
b = Sxy / Sxx
b = { 2312 [ 37 * 422 ] / 6 } / 337 - 37^2 / 6 = -2.67
a = -2.67 * 37/6 = 86.784
Answer:
4095
Step-by-step explanation:
Answer:
Step-by-step explanation:
To find the quotient we need to apply long division on , as follows:
- Divide
Divide the leading coefficients of the numerator and the divisor
Quotient =
Multiply by =
Subtract from to get new remainder
Remainder =
Therefore
2. Divide
Divide the leading coefficients of the numerator and the divisor
Quotient =
Multiply by =
Subtract from to get new remainder
Remainder =
Therefore
3. Divide
Divide the leading coefficients of the numerator and the divisor
Quotient = 3
Multiply by 3 =
Subtract from to get new remainder
Remainder = 0
Therefore