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Mekhanik [1.2K]
3 years ago
8

Please awnserr???????

Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

y = x + <u>43</u>

Step-by-step explanation:

y = x + ?

For (5, 48):  48 = 5 + ?

? = 43

------------

For (7,50):  50 = 7 + ?

? = 43

The others are the same.  The missing number is <u>43.</u>

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Yuan makes punch by mixing cranberry juice and pineapple juice. For every 3 cups of punch, he uses 2 cups of cranberry juice. Dr
Aleks [24]

Answer:

10 cups of canberry juice

Step-by-step explanation:

Given that  for every 3 cups of punch, he uses 2 cups of cranberry juice.

we need to find the number of canberry juice needed to make 15 cups of punch

3 cup's of punch ---> 2 cups of canberry juice

15 cups's of punch ----> x cups of canberry juice

on cross multiplication we get

3\times x=15\times2

x = 10

Therefore we need 10 cups of canberry juice

6 0
3 years ago
Using the slope​ formula, find the slope of the line through the given points.
UNO [17]

Answer:

0

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

  = (-5--5)/ (9--8)

 = (-5+5)/(9+8)

 = 0/17

=0

The slope it 0

This is a horizontal line because the y value doesn't change.  If the y value doesn't change, the slope it zero.

4 0
3 years ago
the diameters of Douglas firs grown at a Christmas tree farm are normally distributed with a mean of 4 inches and a standard dev
aksik [14]

Answer:

Proportion of the trees will have diameters between 2 and 6 inches = 0.8164

Step-by-step explanation:

Given -

Mean (\nu )  = 4

Standard deviation (\sigma  ) = 1.5

Let X be the diameter of tree

proportion of the trees will have diameters between 2 and 6 inches =

P(2<  X<  6)   =  P(\frac{2 - 4 }{1.5}< \frac{X - \nu }{\sigma}<  \frac{6 - 4 }{1.5})

                         = P(\frac{-2 }{1.5}< Z<  \frac{2 }{1.5})     Put  [Z = \frac{X - \nu }{\sigma}]

                         =  P(-1.33< Z<  1.33)

                          = (Z<  1.33) - (Z<  -1.33)

                          = .9082 - .0918

                           = 0.8164

6 0
4 years ago
The first blanks options are -2 , -1/2 , 2 , 1/2
Pie

Answer:

equation 1

y = -2x

equation 2

y = x-3

Solution to both

(1,-2)

Step-by-step explanation:

We need to get the equations of both lines

General form is;

y = mx + c

where m is slope and c is the y-intercept

Table 1

since we have a point 0,0; the y-intercept here is zero

Let us get the slope. We can do this by selecting any two points

m = (y2-y1)/(x2-x1)

m = (2-10)/(-1+5) = -8/4 = -2

So the equation of the first line is;

y = -2x

Table 2

we get the slope

m = (4+2)/(7-1) = 6/6 = 1

The partial equation is;

y = x + c

To get c, we select any two point and substitute

4 = 7 + c

c = 4-7

c = -3

So the equation is;

y = x-3

To get the solution to both systems, we equate the y

-2x = x - 3

-2x-x = -3

-3x = -3

x = -3/-3

x = 1

To get y, we substitute;

recall; y = -2x

y = -2(1)

y = -2

Solution to the system is;

(1,-2)

7 0
3 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
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