Answer:
1.36m/s
Explanation:
We are given that
Mass of one acrobat,
Mass of another acrobat,
We have to find their velocity immediately after they grab onto each other.
The collision between two acrobat is inelastic
According to law of conservation of momentum
Substitute the values
Answer:
assume nitrogen is an ideal gas with cv=5R/2
assume argon is an ideal gas with cv=3R/2
n1=4moles
n2=2.5 moles
t1=75°C <em>in kelvin</em> t1=75+273
t1=348K
T2=130°C <em>in kelvin</em> t2=130+273
t2=403K
u=пCVΔT
U(N₂)+U(Argon)=0
<em>putting values:</em>
=>4x(5R/2)x(Tfinal-348)=2.5x(3R/2)x(T final-403)
<em>by simplifying:</em>
Tfinal=363K
1) Length of the wire.
2) Thickness of the wire.
3) Temperature.
4) Type of metal.
Hope this helps!
-Payshence
Answer:
The total momentum of the cat and the dog is, p = 2.4 kg m/s
Explanation:
Given,
The mass of the cat, m = 800 g
= 0.800 kg
The mass of the dog, M = 1000 g
= 1 kg
The velocity of the cat taken positive x direction, v = 8 m/s
The velocity of the dog, V = - 4 m/s
The momentum of the body is defined as the product of its mass and velocity.
p = mv
The momentum of the cat,
p₁ = 0.8 x 8
= 6.4 kg m/s
The momentum of the dog,
p₂ = MV
= 1 x -4
= -4 kg m/s
The total momentum,
p = p₁ + p₂
= 6.4 + (-4)
= 2.4 kg m/s
Hence, the total momentum of the cat and the dog is, p = 2.4 kg m/s
If m has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object. If the magnification is positive, the image is upright compared to the object; if m is negative, the image is inverted compared to the object