Answer:
d) The three balls experience the same acceleration, the gravitational acceleration of 9.8 m/s2.
Answer:
The angular speed is 0.83 rad/s.
Explanation:
Given that,
Mass of disk M=49 kg
Radius = 1.7 m
Mass of child m= 29 kg
Speed = 2.6 m/s
Suppose if the disk was initially at rest , now how fast is it rotating
We need to calculate the angular speed
Using conservation of momentum
Put the value into the formula
Hence, The angular speed is 0.83 rad/s.
Answer:
a). M = 20.392 kg
b). am = 0.56 (block), aM = 0.28 (bucket)
Explanation:
a). We got N = mg cos θ,
f =
=
If the block is ready to slide,
T = mg sin θ + f
T = mg sin θ + .....(i)
2T = Mg ..........(ii)
Putting (ii) in (i), we get
M = 20.392 kg
b). .............(iii)
Here, l = total string length
Differentiating equation (iii) double time w.r.t t, l, h and h' are constants, so
.....................(iv)
We got, N = mg cos θ
∴
................(v)
Mg - 2T = M
(from equation (iv))
.....................(vi)
Putting (vi) in equation (v),
Using equation (iv), we get,
Unlike bacteria, archaea cell walls
do not contain peptidoglycan.
Archaea have different membrane
lipid bonding compared to Bacteria
and Eucarya.
Archaea have different metabolic pathways.
<u><em>Metabolic differences:
</em></u>
Archaea are very metabolically diverse, so
they are hard to generalize.
Archaea do not use glycolysis pathway to
break down glucose (though they do use
similar pathways).
Many archaea do not have functional Kreb’s
cycle pathways (but some do).
Answer:
The vertical distance traveled is 3.18 m.
Explanation:
In order to find the vertical distance traveled by a body in free fall motion, starting from rest to a velocity of 7.9 m/s. For this purpose, we use Newton's third equation of motion,
2as = Vf² - Vi²
where,
a = g = 9.8 m/s²
s = vertical distance = Δy = ?
Vf = final velocity = 7.9 m/s
Vi = initial velocity = 0 m/s
Therefore,
2(9.8 m/s²)Δy = (7.9 m/s)² - (0 m/s)²
Δy = (7.9 m/s)²/(2)(9.8 m/s²)
<u>Δy = 3.18 m</u>