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3 years ago

Light passes through the following structures in which order

Physics

1 answer:

VladimirAG [237]3 years ago

3 0

Question:The complete question can be found in the attached image below.

Answer: Light passes through the eyes through the following correct order

cornea--> aqueous humor---> lens -------------------->vitreous humor.

Explanation:

The CORNEA is a dome shaped structure that covers the anterior part of the eye. Light rays passes through it first as it enters the eye. The AQUEOUS HUMOR is located anterior to the lens which nourishes the lens and helps to maintain intraocular pressure. Light rays pass through it to the LENS. The lens is a clear structure inside the eye that focuses light rays onto the retina. The light rays passes from lens to the VITREOUS HUMOR before reaching the retina. vitreous humor is a jelly-like substance that fills the center of the eye. I hope this helps, thanks

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Se denomina asi al movimiento de particulas con carga eléctrica en determinada dirección.

andrey2020 [161]

Answer:

si la. carga es positiva experimenta una fuerza en el sentido del campo

en cambio si la carga es negativa,experimenta una fuerza en sentido contrario al campo

3 0

3 years ago

A + 32.2 μC charge feels a 0.544 N force from a + 12.3p μC charge. How far apart are they? (u stands for micro.) [?] m

love history [14]

Answer:

r = 2.55 m

Explanation:

Given that,

First charge, q₁ = 32.2 μC

Second charge, q₂ = + 12.3 μC

The force between charges, F = 0.544 N

We need to find the distance between charges. The force between two charges is given by the formula as follows :

$F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m$

So, the charges are 2.55 m apart.

5 0

3 years ago

A 2.0-kg ball is at rest when a horizontal force of 5.0 N is applied. In the absence of friction, what is the speed of the ball

Rzqust [24]

Answer:

v = 7.1 m/s

Explanation:

Work applied will change kinetic energy

Fd = ½mv²

v = √(2Fd/m) = √(2(5.0)(10) / 2.0) = √50 = 7.07... m/s

7 0

3 years ago

If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net

DIA [1.3K]

I think you would do 20+7 = 27N as the net force

7 0

3 years ago

Read 2 more answers

How are Newton’s second and third laws of motion important to your everyday life?

Rasek [7]

Well, first off, Newtons second law of motion deals with the motion of accelerating and decelerating objects.
We already know that from everyday life examples such as simply pushing a car that if 2 people push a car on a flat road it will accelerate faster than if one person was pushing it... Therefore, there is a relationship between the size of the force and the acceleration.
Now onto the third law of motion. First of all, what is the third law of motion? Well, a force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions! According to Newtons third law, whenever one object, and another object interact with each other, they exert forces upon each other. "For every action, there is an equal and opposite reaction." The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. So, how is this important to everyday life you may ask?
Well, the action-reaction force pairs are found everywhere in your body.
For example, right now as I am typing, my tendons are exerting forces on bones, and those bones exert reaction forces on the tendons, as muscles contract, pulling my fingers on the keys. I press on those keys, and they press back on my fingers. See? Since i'm pressing on the keys, the press back on me. Its opposite from each other, as stated in the quite above. "For every action, there is an equal and opposite reaction."

3 0

4 years ago