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Mrac [35]
2 years ago
9

HEY CAN ANYONE PLS ANSWER DIS MATH PROBLEMS

Mathematics
2 answers:
Dmitrij [34]2 years ago
4 0

Answer:

1. 7i

2. 7 + 6i

3. 4i

4. -15i

5. -5-9i

6. 11 + i

7. 2 + i

8. i + 4

Step-by-step explanation:

PLZ mark brainliest, I can't DM people

shutvik [7]2 years ago
4 0

Answer:

1) 7i

2) 7+6i

3)4i

4)-15i

5)-9i-5

6)15+1

7) i+2

8)-2+i

Step-by-step explanation:

1)combine like terms there are 7 i's

2)combine like terms can add 3+4(can't add 6i)

3)combinelike terms theres 4 i's

4)same there are -15i 's

5)there are 9 - i 's and -1+ (-4)=-5

6)combine like  terms

7) combine like  terms

8)combine like  terms

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8 0
3 years ago
David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the
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Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

  • A(t) is the amount of money after t years.  
  • P is the principal(the initial sum of money).  
  • r is the interest rate(as a decimal value).  
  • n is the number of times that interest is compounded per year.  
  • t is the time in years for which the money is invested or borrowed.

In this problem:

  • The APR is of 2.25%, hence r = 0.0225.
  • No information about the number of compounding per year, hence n = 1.

Item a:

P = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}

A(8) = 2389.66

Item b:

A(t) = 4000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}

(1.0225)^t = 2

\log{(1.0225)^t} = \log{2}

t\log{1.0225} = \log{2}

t = \frac{\log{2}}{\log{1.0225}}

t = 31.15

Item c:

A(3) = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}

P = \frac{2000}{(1.0225)^3}

P = 1870.85

A similar problem is given at brainly.com/question/24850750

7 0
2 years ago
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