Answer:
1.14 × 10³ mL
Explanation:
Step 1: Given data
- Initial volume of the gas (V₁): 656.0 mL
- Initial pressure of the gas (P₁): 0.884 atm
- Final volume of the gas (V₂): ?
- Final pressure of the gas (P₂): 0.510 atm
Step 2: Calculate the final volume of the gas
If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL
The question is incomplete. the complete question is:
A chemistry student needs 35.0 g of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is . Calculate the volume of pentane the student should pour out.Round your answer to 3 significant digits.
Answer: The volume of pentane the student should pour out is 55.9 ml
Explanation:
Density is defined as the mass contained per unit volume.
To calculate volume of a substance, we use the equation:
We are given:
Density of pentane =
Mass of pentane = 35.0 g
Putting values in above equation, we get:
(Conversion factor: )
Hence, the volume of pentane is 55.9 ml
Proton 26
neutron 0
you can tell how many proton by the atomic number
Answer:
the concentration of hydrogen iodide will be higher than it was in the original equilibrium conditions.
Answer:
168.56 mL
Explanation:
density = mass/volume, use basic algebra skills to replace the volume and solve