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scZoUnD [109]
2 years ago
12

^^^can some one help?

Mathematics
1 answer:
Vesna [10]2 years ago
4 0

-\dfrac 89 \times -\dfrac 67 = \dfrac{48}{63}

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Please help me don’t know how to do it,
Vikki [24]

Answer:

7=60

6=60

5=120

4=120

2=60

1=120

3 0
3 years ago
A person purchased 10 items to donate to a school. They bought backpacks that cost $25.75 each and notebooks that cost $4.25 eac
krek1111 [17]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
A half-marathon is 13.1 miles long. There is a water station every 1 1/3 miles along the race trail and at the finish line. How
pashok25 [27]

Answer:

10 water stations are needed

Step-by-step explanation:

To get the number of water- station needed, we simply divide the total length of the half marathon by the distance where we can find a water station

mathematically,

that would be 13.1 divided by 1 1/3

= 13.1 divided by 4/3

= 13.1 * 3/4 = 9.825 which is approximately 10

8 0
3 years ago
When this kettle is full of water it has a mass of 2900 grams. When the kettle is half full of water it has a mass of 2050 grams
Sati [7]
If you would like to know the mass of the kettle when it is empty, you can calculate this using the following steps:

2900 grams - 2050 grams = 850 grams (half of water)

2050 grams - 850 grams = 1200 grams (no water)

The correct result would be 1200 grams.
4 0
3 years ago
Dont leave any links please
Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

\displaystyle \large{ {(mn)}^{b} =  {m}^{b} {n}^{b}   } \\  \displaystyle \large{ {n}^{ - b} =   \frac{1}{ {n}^{b} }    }

We are given the expression:

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } }

Use the first law of exponent above.

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) }   } \\  \displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{2 } {n}^{  - 1}   }

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\   \displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{2 } ( \frac{1}{ {n} } )} \\

Multiply m in.

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =   \frac{ {m}^{2} }{ {n} } }

Thus the answer is m^2/n.

6 0
3 years ago
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