Given that S<span>am's distribution of meal costs has a mean of $9 and a standard deviation of $3, this means that the range of Sam's meal cost that are within one standard deviation is given by ($9 - 3, $9 + 3) = ($6, $12).
Given that Sam </span><span>always tips the server $2 plus 10% of the cost of the meal, this means that when the cost of the meal is $9, Sam tips $2 + (0.1 x 9) = $2 + $0.9 = $2.90
Therefore, the mean of the distribution of Sam's tips is $2.90
Similarly, the </span><span>range of Sam's tips that are within one standard deviation is given by ($2 + 0.1(6), $2 + 0.1(12)) = ($2 + 0.6, $2 + 1.2) = ($2.6, 3.2) = ($2.9 - $0.3, $2.9 + $0.3)
Therefore, </span><span>the standard deviation of the distribution of Sam's tips is $0.3</span>
Answer: (72.535, 76.665)
Step-by-step explanation:
The confidence interval for population mean is given by :-
, where 
= population standard deviation.
n= Sample size
= sample mean.
= Critical z-value (two-tailed)
Given : 
n= 81
The critical values for 90% confidence interval : 
Now, the confidence interval for population mean would be :
Hence, a 90 percent confidence interval estimatefor the average score of all students. : (72.535, 76.665)
sin = 3/7
1 = sin²0 + cos²0
cos²0 = 1 - 9/49
cos²0 = 40/49
cos0 = √(40) / 7
since its in Quadrant 2 the sin is positive and cos is negative
cos0 = - √(40) / 7
Answer:
Domain- -4,-2,0,2 Range- -3,0,2,3,5
Step-by-step explanation:
(x,y)
The domain is the x
The range is the y
And if the number is there more than once you only have to list it once.
Typically you list them from least to greatest so the smallest number the higher number.
