Answer with Step-by-step explanation:
We are given that A, B and C are subsets of universal set U.
We have to prove that

Proof:
Let x
Then
and 
When
then
but 
Therefore,
but 
Hence, it is true.
Conversely , Let
but 
Then
and
When
then 
Therefor,
Hence, the statement is true.
The area of a square is Side x Side. Since its sides are equal you have:
S*S = 1.69
S^2 = 1.69
S = √(1.69)
S= 1.3 km
Hope this help :).
Answer:
False
Step-by-step explanation:
Answer:
Step-by-step explanation:
X^2-12x+36=0
X^2 - 8x - 4x + 36 = 0
(x^2 -8x) - (4x - 36) = 0
x(x - 8) - 4(x - 8) = 0
(x - 4)(x - 8) = 0
:- x - 4 = 0 or x - 8 = 0
x = 4 or x = 8
Consecutive means in order. So let's call the first integer x. The next number in line would be x+1 and the largest integer would be x+2. Let's prove that so you're not confused. If x is 3, then x+1 is 4 (next in line), and x+2 is 5 next after that. See? So if we add all those together we set them equal to 267 and solve for x: x + x+1 + x+2 = 267. Combining like terms gives us 3x + 3 = 267 and 3x = 264. Now dividing both sides by 3 we get that x = 88. That's the smallest integer; the largest is found by adding 88 + 2 which is 90. So that means that the numbers are 88, 89, 90, and that adding them up = 267. Let's check that now: 88+89+90=267 so we're good.