Ok, the formula to find the area of a regular polygon is...
A = 1/2 nsr
In this equation...
n = number of sides
s= side length
r = apothem (radius of the inscribed circle)
To find the area, we must first find the apothem. The apothem is the radius of the inscribed circle (draw a line from the center of the figure to the center of one of the sides). If you draw the apothem in to the figure, it creates a right triangle with a hypotenuse of 13.07 in and one side length of 5 in (1/2 of the figure's side length). Now we can find the apothem with the formula
a^2 + b^2 = c^2
a^2 = c^2 - b^2
a^2 = 13.07^2 - 5^2
a^2 = 170.8249 - 25
a^2 = 145.8249
a = 12.076
Now we have the value for the apothem and we can plug it into the area formula...
A = 1/2 nsr
(recall that n = number of sides; s= side length; r= apothem)
A = 1/2(8×10×12.076)
A = 40×12.076
A= 483.04 in^2
Rounded to the nearest tenth would be...
483.0 in^2
9514 1404 393
Answer:
a) $540 cost to paint
b) 72000 liters to fill
Step-by-step explanation:
Relevant formulas are ...
P = 2(L +W) . . . . perimeter of a rectangle of length L and width W
A = LW . . . . . . area of a rectangle of length L and width W
V = LWH . . . volume of a cuboid of length L, width W, and height H
__
a) The total painted area is the area of the pool walls plus the area of the pool bottom. The wall area is the product of pool perimeter and wall height. The bottom area is the product of pool length and width.
A = PH + LW = 2(L +W)H +LW
A = 2(8 m +6 m)(1.5 m) + (8 m)(6 m) = 42 m² +48 m² = 90 m²
At $6 per square meter, the cost of painting the pool is ...
($6 /m²)(90 m²) = $540 . . . . cost to paint the pool
__
b) The volume in liters is best figured using the dimensions in decimeters.
V = (80 dm)(60 dm)(15 dm) = 72000 dm³ = 72000 L
72000 liters will be needed to fill the pool.
Lowest to Highest
-10, -8, -3, 10, 12
That’s a lot of children. I don’t know the answer but I have some ideas. So I’d 560 is then basically equal to 40 over x so then about 1400