All categories

3 years ago

What is another term for linear diameter?

Physics

2 answers:

slega [8]3 years ago

6 0

B)angular diameter because it’s the correct answers and it answers the question

Semenov [28]3 years ago

5 0

The answer is B, angular diameter.

You might be interested in

An airplane is traveling at a fixed altitude with an outside wind factor. The airplane is headed N 40° W at a speed of 600 miles

bija089 [108]

Answer: $\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]$

Explanation:

Given

Plane is initially flying with velocity of magnitude $v=600\ mph$

at angle of $40^{\circ}$ with North towards west

Velocity of plane airplane can be written as

$v_a=600(-\sin 40\hat{i}+\cos 40\hat{j})$

Now wind is encountered with speed of $v=80\ mph$ at angle of $N45^{\circ}E$

$v_w=80(\cos 45\hat{i}+\sin 45\hat{j})$

resultant velocity

$\vec{v_R}=\vec{v_a} +\vec{v_w}$

$\vec{v_R}=600(-\sin 40\hat{i}+\cos 40\hat{j})+ 80(\cos 45\hat{i}+\sin 45\hat{j})$

$\vec{v_R}=\hat{i}[-385.67+56.56]+\hat{j}[459.62+56.56]$

$\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]$

for direction $\tan \theta =\frac{516.18}{329.11}$

$\tan \theta =1.568$

$\theta =57.47^{\circ}$ west of North

3 0

4 years ago

a 2kg ball moving at speed 5m/s hits a wall .the force exerted by the wall on the ball is 100n .if the collision is perfectly el

levacccp [35]

Answer:

0.2s

force = change in momentum/ time

time = change in momentum/time

Explanation:

first, let's find the change in momentum

pf-pi

5×(-2) - 5× 2

-20kgm/s = 20kgm/s(by changing the direction of whole system)

time = change in momentum/time

20/100

0.2s

4 0

3 years ago

Answer only number 6

harina [27]

Answer:

Answer A. Fission, steam, turbine, electricity, cool water

Explanation:

Nuclear Energy Production

Nuclear energy is produced by splitting uranium atoms in a process called fission. This generates heat and it's managed to produce steam, which later is used by a turbine generator to generate electricity. The heat must be taken out of the system, so a cooling process, usually involving water is the final step.

Because nuclear power plants don't burn fuel, they are known as clean energy sources.

Answer A. Fission, steam, turbine, electricity, cool water

6 0

3 years ago

The planet Uranus has a radius of 25,360 km and a surface acceleration due to gravity of 9.0 m/s^2 at its poles. Its moon Mirand

AlexFokin [52]

Answer:

$8.67791\times 10^{25}\ kg$

$0.34589\ m/s^2$

$0.07903\ m/s^2$

Explanation:

M = Mass of Uranus

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Uranus = 25360 km

h = Altitude = 104000 km

$r_m$ = Radius of Miranda = 236 km

m = Mass of Miranda = $6.6\times 10^{19}\ kg$

Acceleration due to gravity is given by

$g=\dfrac{GM}{r^2}\\\Rightarrow M=\dfrac{gr^2}{G}\\\Rightarrow M=\dfrac{9\times 25360000^2}{6.67\times 10^{-11}}\\\Rightarrow M=8.67791\times 10^{25}\ kg$

The mass of Uranus is $8.67791\times 10^{25}\ kg$

Acceleration is given by

$a_m=\dfrac{GM}{(r+h)^2}\\\Rightarrow a_m=\dfrac{6.67\times 10^{-11}\times 8.67791\times 10^{25}}{(25360000+104000000)^2}\\\Rightarrow a_m=0.34589\ m/s^2$

Miranda's acceleration due to its orbital motion about Uranus is $0.34589\ m/s^2$

On Miranda

$g_m=\dfrac{Gm}{r_m^2}\\\Rightarrow g_m=\dfrac{6.67\times 10^{-11}\times 6.6\times 10^{19}}{236000^2}\\\Rightarrow g_m=0.07903\ m/s^2$

Acceleration due to Miranda's gravity at the surface of Miranda is $0.07903\ m/s^2$

No, both the objects will fall towards Uranus. Also, they are not stationary.

6 0

3 years ago

Someone please help. Describe how electric potential energy, kinetic energy, and work change when two charges of opposite sign a

erik [133]

Answer:

The answer is based on the conservation of energy law; something you should really understand by now.

For convenience we can hold one of the two charges still; it becomes the frame of reference. And everything we say is in reference to the designated static charge, call it Q.

So the moving charge, call it q, has total energy TE = PE. It's all potential energy as we start with q not moving.

It has potential energy because in order to separate q from Q, we had to do work, add energy, on q. And from the COE law, that work added is converted into PE.

It's a bit like lifting something off the ground. That's work and it becomes GPE. So there's some work, in separating the two charges in the first place.

But there's more.

Now we let q go. As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.

And there's more work, done by the EMF on charge q. That converts the PE into KE and the q charge smashes into Q with some kinetic energy.

5 0

3 years ago