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katrin2010 [14]
3 years ago
8

SOLVE THIS PROBLEM ASAP

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

6,6

There are 8 spaces in bettween  point a and b so 8/2 = 4 so 4 up from point a is 6,6

Step-by-step explanation:

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Brainliest to whoever answers first!!!Z'(5, -7) is the image of Z after a reflection
lara [203]

Answer:

I think its Z (-5, 7)

Step-by-step explanation:

Here :)

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3 years ago
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S varies inversely as G. If S is 4 when G is 1.8, find S when G is 6.
Reika [66]

Given that "S" varies inversely as "G", it is an Inverse Variation Relationship. Then, it has this form:

S=\frac{k}{G}

Where "k" is the Constant of Variation.

Knowing that:

S=4

When:

G=1.8

You can substitute values and solve for "k":

\begin{gathered} 4=\frac{k}{1.8} \\  \\ (4)(1.8)=k \\  \\ k=7.2 \end{gathered}

Then, the equation that models the situation is:

S=\frac{7.2}{G}

Substituting this value of "G" into the equation and evaluating:

G=6

You get:

S=\frac{7.2}{6}=1.2

Hence, the answer is:

S=1.2

4 0
1 year ago
Can someone PLEASE answer the Algebra Question CORRECTLY BELOW!
Maru [420]

From The picture 2 barrels = 73 gallons

Divide by 2 for gallons per barrel:

73/2 = 36.5 gallons per barrel

Multiply gallons per barrel barrels:

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Giving brainly for correct answer
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Six (I’m putting this because there is a there is less than 20 characters)
7 0
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Forty-seven percent of fish in a river are catfish. Imagine scooping out a simple random sample of 25 fish from the river and ob
Romashka-Z-Leto [24]

Answer: The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 fish in the river.

Step-by-step explanation:

The standard deviation of the sampling distribution = \sqrt{\dfrac{p(1-p)}{n}} , where p= population proportion and n = sample size.

Let p be the proportion of  fish in a river are catfish.

As per given , we have

p= 0.47

n= 25

The, the standard deviation of the sampling distribution will be \sqrt{\dfrac{0.47(1-0.47)}{25}}

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The 10% condition : Sample sizes should be no more than 10% of the population.

But a river can have more than 250 fish [where 10% of 250 =25 (sample size)]

i.e. The 10% condition is met because it is very likely there are more than 250 fish in the river.

So the correct answer is "The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 fish in the river."

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