The balanced chemical reaction is:
C6H6 + 9/2O2 = 6CO + 3H2O
We are given the amount of benzene to be used for the reaction. This will be the starting point for the calculations.
23.1 g C6H6 ( 1 mol C6H6 / 78.12 g C6H6 ) ( 6 mol CO / 1 mol C6H6 ) = 1.77 mol CO is produced from the reaction
Answer: 165 g
Explanation: solution attached:
Density is expressed as mass per unit volume
d = m/V
Derive to find mass
m= dV
= 1.10g/mL x 150 mL
= 165 g
Cancel out mL and the remaining unit is in g.
Answer:
a. 1/3
In the picture- D. 4
Explanation:
The product of the gradients of perpendicular lines =-1
m1m2=-1
Given an equation of a line in the form y=mx+c, m is the gradient of the line.
For y= -3x-9, m=-3
m1m2=-1
-3×m2=-1
m2=1/3
The gradient of the perpendicular line is 1/3
For the question in the picture, y=-1/4x-9, m=-1/4
m1×m2=-1
-1/4m2=-1
m2=4
The slope of the line perpendicular to y=-1/4x-9 is 4
Explanation:
if the solution placed on the chromatography is pure there will be formation of one spot from the baseline and will go farthest to the front line unlike the impure one
Answer:
0
Explanation:
they cancel each other out (ex: 1 positive and 1 negative cancels, making it neutral or a charge of 0)