The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
The given parameters;
- mass of the car, m = 1400 kg
- Initial velocity of the car, u = 25 m/s
- coefficient of kinetic friction, μ = 0.7
The acceleration of the car is calculated as follows;
a = μg
a = 0.7 x 9.8
a = 6.86 m/s²
The time taken for the car to stop is calculated by using Newton's second law of motion;
F = ma
Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
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Yes it does ! Uh huh. Right you are. Truer words are seldom written.
You have quoted the law quite accurately but also incompletely.
Do you have a question to ask ?
Answer:
Er = 231.76 V/m, 27.23° to the left of E1
Explanation:
To find the resultant electric field, you can use the component method. Where you add the respective x-component and y-component of each vector:
E1:
E2:
Keep in mind that the x component of electric field E2 is directed to the left.
∑x: 
∑y: 
The magnitud of the resulting electric field can be found using pythagorean theorem. For the direction, we will use trigonometry.
or 27.23° to the left of E1.
Answer:
Por lo tanto, la presión del ozono es:
Explanation:
Podemos usar la ecuacion de los gases ideales;
(1)
Tenemos:
El volumen V = 224 dm³ = 224 L
La temperatura T = 51.09 C = 324.09 K
La masa es m = 4.561 kg
Lo necesitamos ahora es calvular n que es el numero de moles;
recordemos que el peso molecular del ozono M = 48 g/mol.
Finalmente, usando la ecuacion 1 despejamos la presion P
Por lo tanto, la presion del ozono es:
Espero te haya ayudado!
