Can anyone please help me with this??? I really need it );
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For x-intercept,
y = 0,
log(3x+3) = 2
(3x + 3) = antilog(2)
x = (antilog(2) - 3)/3
x ≈ 32.3333
For y-intercept,
x = 0,
y = log(3) - 2
y ≈ -1.5228
For x-intercept,
y = 0,
log(3x+3) = 2
(3x + 3) = antilog(2)
x = (antilog(2) - 3)/3
x ≈ 32.3333
For y-intercept,
x = 0,
y = log(3) - 2
y ≈ -1.5228
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