Question

Be sure to answer all parts. Dinitrogen difluoride, N2F2, is the only stable, simple inorganic molecule with an N=N bond. The compound occurs in cis and trans forms. (a) Select which of the molecular shapes of N2F2 correspond to the cis and trans form of N2F2. I h5a II h5b III h5c cis-dinitrogen fluoride: I II III trans-dinitrogen fluoride: I II III (b) Predict the polarity, if any, of each form. cis = polar; trans = polar cis = polar; trans = nonpolar cis = nonpolar; trans = polar cis = nonpolar; trans = nonpolar

Answer 1

Answer:

(a) The molecular shapes of cis and Trans forms of N2F2 are-

b) There is EN difference between N atom and F atom. Hence the molecule will have a bond dipole.

In Cis form two fluorine atoms are on the same side of N N bond. Hence, bond moment in N2F2 cis form) do not cancel each other. Thus the cis form is polar.

In the trans form two fluorine atoms are on the opposite side of N-N bond. Bond moment of NF cancels each other.

Thus: trans N2F2 is non polar molecule.

Answer 2

(a) The molecular shapes of cis and Trans forms of N2F2 are-

b) There is EN difference between N atom and F atom. Hence the molecule will have a bond dipole.

In Cis form two fluorine atoms are on the same side of N N bond. Hence, bond moment in N2F2 cis form) do not cancel each other. Thus the cis form is polar.

In the trans form two fluorine atoms are on the opposite side of N-N bond. Bond moment of NF cancels each other.

Thus: trans N2F2 is non polar molecule.