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1 year ago

Pls answer i will fail:-}

Mathematics

2 answers:

murzikaleks [220]1 year ago

5 0

Answer:

Graphic Representation of the Equations is in the image above

Step-by-step explanation:

Solve by Substitution :

// Solve equation [2] for the variable y

[2] y = 4x - 5

// Plug this in for variable y in equation [1]

[1] (4x-5) - 2x = -1

[1] 2x = 4

// Solve equation [1] for the variable x

[1] 2x = 4

[1] x = 2

// By now we know this much :

y = 4x-5

x = 2

// Use the x value to solve for y

y = 4(2)-5 = 3

Solution :

{y,x} = {3,2}

True [87]1 year ago

3 0

Answer:

Part 1:

You can solve the pair of equation graphically by writing the y-intercepts which are (0,-1) and (0,-5) Then follow the slopes of each line till the intercept. The slopes are up 2 over 1 and up 4 over 1 respectivily

Part 2:

When you graph these you get the answer of (2,3)

x is 2 and y is 3

Step-by-step explanation:

Hope it helps :)

pls mark brainliest :P

*insert British accent* "Don't just let 'em take it!"

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How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

6 0

2 years ago

[Systems of equations] (/20) 1. Suppose the coefficient matrix of a system of linear equations has a pivot position in every row

Marina86 [1]

Answer:

The system is consistent because the rightmost column of the augmented matrix is not a pivot column.

Step-by-step explanation:

It is given that the coefficient of the matrix of a linear equation has a pivot position in every row.

It is provided by the Existence and Uniqueness theorem that linear system is said to be consistent when only the column in the rightmost of the matrix which is augmented is not a pivot column.

When the linear system is considered consistent, then every solution set consists of either unique solution where there will be no any variables which are free or infinitely many solutions, when there is at least one free variable. This explains why the system is consistent.

For any m x n augmented matrix of any system, if its co-efficient matrix has a pivot position in every row, then there will never be a row of the form [0 .... 0 b].

6 0

2 years ago

Please help with geometry homework!!!!

EleoNora [17]

Area of Parallelogram ABCD is equivalent to the area of rectangle AXBY.

Area of rectangle AXBY= Length AX * Length AB= 3 ft * 4√2 ft = 12√2 sq.ft.

Thus Area of Parallelogram is 12√2 sq.ft.