Answer:
The awnser for "Electricity that flows in a closed path is called a" circuit.
Momentum is conserved.
p = m₁v₁ + m₂v₂ = constant
Momentum before the collision(kick):
p = 80 * 0 + 4 * 0 = 0
Momentum after the collision:
p = 80 * v₁ + 4 * 15 = 0
Solve for v₁.
Answer: 15.29
Explanation: there you go have a nice day (*^p^*)
Question: A charge of 0.50 C moves horizontally in a magnetic field of 1.0 T with a speed of 4.0 x 10^⁻1 m/s. The force experienced by the charge is 7.0 N. What is the angle between the charge direction and the magnetic field?
Answer:
Θ = 6.56°
Explanation:
From the question,
Using
F = BvqsinΘ................... Equation 1
Where F = force experienced by the charge, B = magnetic field, q = Charge, Θ = angle between the charge abd the magnetic field, v = velocity.
Make Θ the subject of the equation
Θ =sin⁻¹ (Bvq/F)............... Equation 2
Given: v = 4.0×10⁻¹ m/s, B = 1.0 T, q = 0.50 C, F = 7.0 N
Θ = sin⁻¹(1×0.5×4×10⁻¹/7)
Θ = sin⁻¹(0.114)
Θ = 6.56°