Let the fist integer be x, the second is x+20 the product of the numbers is: x(x+20) the sum of the numbers is: x+x+20=2x+20 the sum of the above operations will give us: 2x+20+x^2+20x=95 x^2+22x+20=95 this can be written as quadratic to be: x^2+22x-75=0 solving the above we get: x=3 and x=-25 but since the integers should be positive, then x=3 the second number is x+20=3+20=23 hence the numbers are: 3 and 23