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ddd [48]
2 years ago
10

Solve each system by substitution.

Mathematics
1 answer:
Kipish [7]2 years ago
6 0
<h3>Solution (1):</h3>

<u>Given:</u>

  • y = 3x - 5
  • y = -6x - 5

<u>Multiplying y = 3x - 5 by 2:</u>

  • => 2(y = 3x - 5)

               y = -6x - 5

  • => 2y = 6x - 10

               y = -6x - 5

<u>Adding both equations:</u>

  • => 3y = -15

<u>Dividing 3 both sides:</u>

  • => y = -5

<u>Substitute the value of y into any equation.</u>

  • y = -6x - 5
  • => -5 = -6x - 5
  • => 0 = -6x

<u>Divide -6 both sides.</u>

  • => x = 0/-6 = 0
<h3>Solution (2):</h3>

<u>Given:</u>

  • y = 8x - 9
  • y = -8x + 7

<u>Add both the equations.</u>

  • y = 8x - 9

        y = -8x + 7

  • 2y = -2

<u>Divide 2 both sides.</u>

  • 2y = -2
  • => 2y/2 = -2/2
  • => y = -1

<u>Substitute the value of y into any equation.</u>

  • y = 8x - 9
  • => -1 = 8x - 9

<u>Add 9 both sides.</u>

  • => -1 + 9 = 8x - 9 + 9
  • => 8 = 8x

<u>Divide 8 both sides.</u>

  • => 8/8 = 8x/8
  • => x = 1
<h3>Solution (3):</h3>

<u>Given:</u>

  • -x + 6y = 21
  • y = -5x + 12

<u>Reorganize the first equation.</u>

  • -x + 6y = 21
  • => 6y = x + 21

<u>Multiply the first equation by 5.</u>

  • 5(6y = x + 21)

          y = -5x + 12

  • 30y = 5x + 105

          y = -5x + 12

<u>Add both the equations.</u>

  • 31y = 117

<u>Divide 31 both sides.</u>

  • 31y = 117
  • => 31y/31 = 117/31
  • => y = 117/31

<u>Substitute the value of y into any equation.</u>

  • -x + 6y = 21
  • => -x + 6(117/31) = 21
  • => -x + 702/31 = 651/31

<u>Subtract 702/31 both sides.</u>

  • => -x = 651/31 - 702/31
  • => -x = -51/31
  • => x = 51/31
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Your answer would be, Point A(4, 2) is translated according to the rule (x, y) ==> (x + 1, y - 5), and then reflected across the Y- Axis.

A.). So, Point A(4, 2) is in the first Quadrant.

B.). The Co-ordinates translated Point A (5, - 3), are in the Fourth Quadrant.; Lower Right

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Reflection Across Y- Axis:

(x, y) ===> ( - x, y) ======> (5, - 3) ====> ( -5, - 3)

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(x, y) ====> ( x + 1, y - 5) =====> ( 4, 2) =====> (5, - 3)

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