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1 year ago

Can someone plssss helpmanipulating algebraic fractions

Mathematics

1 answer:

aalyn [17]1 year ago

3 0

Answer:

the answer is 5x divide by 12

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Evaluate 3^2 + (5-2) X 4 - 6/3

muminat

Answer:

The result is 19

Step-by-step explanation:

$3^{2} + (5-2)x4 - 6/3$

Step 1: Parenthesizing (5-2)=3

$3^{2} + 3x4 - 6/3$

Step 2: Exponentiation $3^{2}=9$

$9 + 3x4 - 6/3$

Step 3: Multiplication and division 3x4=12 and 6/3=2

$9 + 12 - 2$

Step 4: Addition and subtraction 9+12=21, and 21-2=19

21-2

The operations are ordered from highest to lowest in the order:

1. Parenthesizing,

2. Factorial,

3. Exponentiation,

4. Multiplication and division,

5. Addition and subtraction.

Hope this helps!

6 0

2 years ago

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Is the answer to this problem right

Morgarella [4.7K]

Answer:

it should be option 2 and 4

Step-by-step explanation:

6 0

2 years ago

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What is the value of x and y

Anestetic [448]

Step-by-step explanation:

8y+17°=6x+7° (vertical opposite angle)

6x+7=3x-29. (interior angle on same side)

3x=-36

x=-12°

B=C

-72+7=-36-29

-65=-65

6 0

2 years ago

Please help it’s urgent

katrin2010 [14]

$\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}$

<u>Step-by-step explanation:</u>

$.\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}$

5 0

2 years ago

3) (-4.0) - (-3.8) - 1.1<br> Pls I need to know

jeyben [28]

Answer:

-1.3

Hope this helps dont 4get to like and star

-mercury

3 0

2 years ago

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Can someone plssss helpmanipulating algebraic fractions ​

Can someone plssss helpmanipulating algebraic fractions