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Gwar [14]
2 years ago
15

 Find the length of the third side. If necessary, write in simplest radical form.

Mathematics
1 answer:
Stolb23 [73]2 years ago
8 0

Answer:

7

Step-by-step explanation:

As it is a RIGHT triangle, the formula is a^2+b^2=c^2.

We are given one leg and the hypotenuse. That means 4^2x2+b^2=81.

To find 4 root 2 square, you square them individually then multiply.

4^2=16 times 2 (root 2 squared is 2).

Simplified, that gives 16x2=32,

81-32=49.

The last leg is seven.

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3 ratios that are equivalent to 6:12
Burka [1]

Answer:

1:3

2:4

3:6

Step-by-step explanation:

we can divide both sides by 6 and get 1:2

we can divide both sides by 3 and get 2:4

we can divide both sides by 2 and get 3:6

5 0
4 years ago
Read 2 more answers
Complete the equation for the standard form of the line that has an x-intercept of 3 and a y-intercept of 5.
Ugo [173]

Answer:

5x+3y=15

Step-by-step explanation:

We are given two coordinates (3,0) (0,5)

Start by finding slope

y2-y1/x2-x1=  5-0/0-3= -5/3 this is your slope m.

y=mx+c

y= -5/3x+c (but remember standard line is ax+by=c) so we have to switch sides

5/3x + y=5 (remember standard form has no fraction so multiply by 3 on all sides)

5x+3y=15

3 0
3 years ago
Read 2 more answers
Select all the expressions that are equivalent to - 2/5 (15-20d + 5c).
Nostrana [21]
One of them is -6+8d-2c
4 0
3 years ago
Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i
Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333

So the correct answer is C, the area between the two functions is 4/3 units.

3 0
3 years ago
Card
Burka [1]

Answer:

19,27 cm^2

Step-by-step explanation:

area of triangle = (6 x 3)/ 2 = 9 cm^2

circle area : 3^2 x 3,14 = 28,27 cm^2

area of shaped region = 28,27 - 9 = 19,27 cm^2

6 0
3 years ago
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