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Gwar [14]
2 years ago
15

 Find the length of the third side. If necessary, write in simplest radical form.

Mathematics
1 answer:
Stolb23 [73]2 years ago
8 0

Answer:

7

Step-by-step explanation:

As it is a RIGHT triangle, the formula is a^2+b^2=c^2.

We are given one leg and the hypotenuse. That means 4^2x2+b^2=81.

To find 4 root 2 square, you square them individually then multiply.

4^2=16 times 2 (root 2 squared is 2).

Simplified, that gives 16x2=32,

81-32=49.

The last leg is seven.

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What’s ( -13x- 15 ) - ( -9x + 16 )
Tasya [4]

Answer:

-4x-31

Step-by-step explanation:

1) Distribute:

(-13x-15)+(9x-16)

2) Eliminate parenthesis that are not useful:

-13x-15+9x-16

3) Subtract the numbers:

-13x-31+9x

4) Combine like terms:

-4x-31

Hope this helped!

3 0
3 years ago
a trapezoid has an area of 50 square inches. The bases are 3 inches and 7 inches. What is the height of the trapezoid.
charle [14.2K]

Answer: The answer is 10 inches.

Step-by-step explanation:  Given that the area of a trapezoid is 50 square inches and the bases are 3 inches and 7 inches. We are to find the height of the trapezoid.

We know that the area of a trapezoid with height 'h' and bases 'a' inches and 'b' inches is given by

A=\dfrac{a+b}{2}h.

In the given question,

a = 3 inches, b = 7 inches, A = 50 square inches, h = ?

Therefore,

50=\dfrac{3+7}{2}\times h\\\\\\\Rightarrow 50=5h\\\\\Rightarrow h=10.

Thus, the required height is 10 inches.  

8 0
3 years ago
Which solid has zero faces, zero bases, zero vertices, and zero edges?
svlad2 [7]
The only solid <span>zero faces, zero bases, zero vertices, and zero edges is a sphere. The reason why is because it's just round, and it doesn't have anything, just a sphere. 

Have a nice day! :)</span>
3 0
4 years ago
Read 2 more answers
I need help with this asap.
Illusion [34]

Answer:

what do you need help with?

Step-by-step explanation:

3 0
3 years ago
What is the first step in solving a quadratic equation of the form given below? (ax + b)2 = c
Aleonysh [2.5K]
Multiply the 2 into the ax and b, and then moving the c over and changing it's sign

hope this helps
8 0
4 years ago
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