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Natasha2012 [34]
2 years ago
15

Which of the following is the graph of f(x) = cos(x+ +32

Mathematics
1 answer:
Anit [1.1K]2 years ago
7 0

Answer:

B

Step-by-step explanation:

pi / 2 is equal to 180°/2 which is 90°.

Cos (90°) = 0

if cos90 = 0 then what kind of graph will we have at 90° to the x axis ?

a graph passing through the origin. (0,0)

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8% of the rides in the park are water rides. if there are 4 water rides how many rides are there in total
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8/100=4/n 400=8n ___ ____ 8n. 8n 50=n
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Help Please I need help with everything shown on this page
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This question is all about dimensional analysis.  The whole idea behind dimensional analysis is that you multiply a starting value with different conversion factors to cancel out units you don't want to tern the value into the units that you do want.  The conversion for yards to feet can be written as 3 feet/yard (this is the conversion factor it can be written as 3feet/1yard or 1yard/3feet, it depends on what you are starting with).  If you start out with yards and and want to go to feet you have to multiply the number of yards by 3feet/yard so that the yards cancel out leaving you with feet.  If start out with feet and want to go to yards you divide the number of feet by 3feet/yard so that the feet cancel out and you are left with yards.

In your question Tom is trying to go from feet to yards.  Therefore he has to divide the number of feet by 3feet/yard to get feet to cancel out.  His mistake was that he multiplied by 3feet/yard instead of divide by 3feet/yard.  The correct way do it is divide 379 feet by 3feet/yard to get 126.33 yards.

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I hope this helps.
7 0
3 years ago
Kenya exchanges $150 for British pounds(£). Suppose the conversion rate is £1 = $1.60. How many pounds should she receive?
yulyashka [42]
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8 0
3 years ago
Read 2 more answers
Please answer this the best
dexar [7]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is
anastassius [24]

Answer:

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

p_v =2*P(t_{(60)}>1.202)=0.234  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=424 represent the sample mean

s=26 represent the sample standard deviation

n=61 sample size  

\mu_o =420 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 420 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 420  

Alternative hypothesis:\mu \neq 420  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=61-1=60  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(60)}>1.202)=0.234  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

4 0
3 years ago
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