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2 years ago

Picture explains asdasdasd

Mathematics

1 answer:

tamaranim1 [39]2 years ago

7 0

Answer:

Yes, AB is tangent

Step-by-step explanation:

The tangent is perpendicular to the radius. The given triangle is right if AB is tangent.

Use Pythagorean to verify

20² = 16² + 12²
400 = 256 + 144
400 = 400

Confirmed

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I’m in Algebra 2 and we’re currently on the subject of “Solving Absolute Value Equations” and I’m having trouble with this equat

saw5 [17]

let's bear in mind that an absolute value expression is in effect a piece-wise expression, namely it has a ± versions of the same expression.

$\bf 5|3x-4| = x+1\implies |3x-4|=\cfrac{x+1}{5}\implies \begin{cases} +(3x-4)=\cfrac{x+1}{5}\\[1em] -(3x-4)=\cfrac{x+1}{5} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(3x-4)=\cfrac{x+1}{5}\implies 3x-4=\cfrac{x+1}{5}\implies 15x-20=x+1 \\\\\\ 14x-20=1\implies 14x=21\implies x = \cfrac{21}{14}\implies \boxed{x=\cfrac{3}{2}} \\\\[-0.35em] ~\dotfill\\\\ -(3x-4)=\cfrac{x+1}{5}\implies -3x+4=\cfrac{x+1}{5}\implies -15x+20=x+1 \\\\\\ 20=16x+1\implies 19=16x\implies \boxed{\cfrac{19}{16}=x}$

6 0

3 years ago

Select the correct answer.

Papessa [141]

Answer:

Step-by-step explanation:

Where's the graph?

8 0

3 years ago

Read 2 more answers

Lin bought x grams of sugar. Jada bought 3⁄4 more than that. what is the equation that will represents the relationship between

astra-53 [7]

Answer:

y = 7/4x

Step-by-step explanation:

Lin bought x grams of sugar.

Jada bought 3⁄4 more than Lin bought.

The equation:

y = x + 3/4x ⇒ y = 7/4x

3 0

2 years ago

Use the distributive property to write an equivalent expression. 6(s + 3t)

soldier1979 [14.2K]

6s +18t hope this helps

5 0

3 years ago

Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth

pav-90 [236]

Answer:

$\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$ . Let $(x_1,y_1)\rightarrow(5,1)$ and $(x_2,y_2)\rightarrow(3,4)$ , thus:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}$

Therefore, the distance between points P(5,1) and Q(3,4) is $\sqrt{13}$ units.

8 0

2 years ago