Answer:
52.374 cm*3
Step-by-step explanation:
the upper triangle is equal to the bottom triangle
Btw fyi the formula of calculating the value of a prism is:
area of the base × height
Answer:
The answer is 33.2*F (72.3*F - 39.1*F because the temp. is *dropping* 39.1*F)
Step-by-step explanation:
If there is a negative change in temp. then that is just like subtracting the change from the base degree (F)
Answer:
x < 5
Step-by-step explanation:
2 x +8 < 18
Subtract 8 from each side
2x+8-8 < 18 -8
2x< 10
Divide by 2
2x/2 < 10/2
x < 5
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
The best and most correct answer among the choices provided by your question is the second choice or letter B. 12
Substituting b = 12:
x^2 + 12x + 36 = (x + 6) ( X + 6) ; therefore, a perfect square.
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