The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
Answer:
f(x)-3x+5 and g(x)=4+5 is it true ?Step-by-step explanation:
Answer:
5/2
Step-by-step explanation:
BRAINLIEST
The trigonometry angle range -π ≤ α ≤ π in radians means angle α is
- between -π radians and π radians or
- -180° and 180°.
To answer the question, we need to know what a trigonometric angle range is
<h3>What is a trigonometric angle range?</h3>
A trigonometric angle range is the range of values which the trigonometric angle can have
Since we need to find the meaning of the trigonometry angle range -π ≤ α ≤π.
We know that
- -π radians = -π × 180°/π = -180° and
- π radians = π × 180°/π = 180°.
Since α is in the range -π ≤ α ≤ π = -180° ≤ α ≤ 180°, this implies that the angle α is
- between -π radians and π radians or
- between -180° and 180°.
So, the trigonometry angle range -π ≤ α ≤ π in radians means that angle α is
- between -π radians and π radians or
- between -180° and 180°.
Learn more about trigonometric angle range here:
brainly.com/question/27971632
#SPJ1