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3 years ago

What is the distance between E(-7, 8) and F(1, -6)? leave in simplified radical form

Mathematics

1 answer:

Serggg [28]3 years ago

5 0

Using distance formula 2 √65

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What will happen to the measures of central tendency if the outlier is removed

frosja888 [35]

It decreases the number of data by one.

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1 year ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$

Substitute point (1, -1) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}$

Equate to find h:

$\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}$

Substitute found value of h into one of the equations to find a:

$\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}$

Substitute found values of h and a to find k:

$\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}$

Therefore, the equation of the parabola in vertex form is:

$\implies y=3(x-0)^2-4=3x^2-4$

So the vertex of the parabola is (0, -4)

5 0

2 years ago

Read 2 more answers

A recipe calls for 2 1/3 cups of flour to make a batch of cookies. How many batches of cookies can be made if you have 11 2/3 cu

MariettaO [177]

Answer:

Good question

Step-by-step explanation:

7 0

2 years ago

I will give brainliest answer

snow_tiger [21]

Step-by-step explanation:

inner region

A=πr^2

A=π*6^2

A=π*36cm^2

A=113.09cm^2

shaded region(outer)

A=πr^2

A=π*9^2

A=π*81cm^2

A=254.46cm^2

Area of shaded region=254.46cm^2-113.09cm^2

=141.37cm^2

Mark brianliest if my answer suit your question

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3 years ago

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Is 5.8 centimeters larger than 590 milimeters

makvit [3.9K]

no it is not, 590 millimeters = 59 centimeters

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3 years ago