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natima [27]
2 years ago
11

The total deposist made over a time of periode

Mathematics
1 answer:
scZoUnD [109]2 years ago
6 0

bro what.... finish the question...

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Which expression gives the best estimate of 45 percent of 76?
zaharov [31]
45 percent of 76= 34.2
6 0
3 years ago
Read 2 more answers
The students at Rudy's school voted between a bear and a lion as the new school mascot. 14 students voted for the bear and 86 st
tino4ka555 [31]

Answer:

14%

Step-by-step explanation:

Given :

Bear voters = 14

Lion voters = 86

Percentage of students who voted bear :

(Bear voters / total number of Voters) * 100%

Total number of voters = (bear voters + lion voters) = (14 + 86) = 100

Percentage of students who voted bear :

(14 / 100) * 100%

0.14 * 100%

= 14%

5 0
3 years ago
Can somebody help me with this question
goblinko [34]

A function is a relationship where each x-value is paired with exactly one y-value.

When looking at a graph, you want to ask yourself, "Can I find any two points on this graph that have the same x-value?"

I can see with x=8 that there would be two points on that graph with an x-value of 8, making this not a function.

People call this test "the vertical line test" because any vertical line really represents a single x-value. If any vertical line hits the graph more than once, the graph cannot be a function, because that value of x has more than one y-value.

8 0
3 years ago
PLS HELP ME!!!!!!!! 99 POINTS
Amiraneli [1.4K]

Answer:

\angle LKN=\arctan1.8\sqrt{97}\approx 86.77^{\circ}

Step-by-step explanation:

Draw the second altitude MB (see attached diagram).

Quadrilateral HLMB is a rectangle, then LM = HB = 3 units.

Trapezoid KLMN is isosceles trapezoid (because KL=MN), thus

KH = BN = \dfrac{KN-HB}{2}=\dfrac{13-3}{2}=5\ units\\ \\HN=HB+BN=3+5=8\ units

Triangle LHN is right triangle, then by Pythagorean theorem,

LN^2=LH^2+HN^2\\ \\89^2=LH^2+8^2\\ \\LH^2=89^2-8^2\\ \\LH^2=(89-8)(89+8)\\ \\LH^2=81\cdot 97\\ \\LH=9\sqrt{97}\ units

Consider right triangle KLH. In this triangle,

\tan\angle LKH=\{\tan\angle LKH\}=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{LH}{KH}=\dfrac{9\sqrt{97}}{5}=1.8\sqrt{97}\ units

So,

\angle LKN=\arctan1.8\sqrt{97}\approx 86.77^{\circ}

5 0
3 years ago
How do you do that problem right there ?
jenyasd209 [6]
Haven't done this in awhile but i got
63x (2/9-6)
63x (0.2-6)
-364
6 0
3 years ago
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