Answer:
FH ~ 10.02
Step-by-step explanation:
1. Approach
One should first find the circumference of the given circle. Then one should find how large the fraction of the circumference one is supposed to find is. Finally, one should multiply the fraction of the circumference one is supposed to find by the total circumference.
2. Circumference of the circle
The formula for circumference is;
π
Substitute in the given values;
It is given that the radius is, hence
2 (7) π
14π
3. Find the fraction of the circumference one is supposed to find
It is given that the angles over the measure of the total degrees of angles in a circle are equal to the arc surrounding the angles of the circumference. Essentially;
Substitute in the given information and solve;
arc = 
arc = 
arc ~ 10.02
Answer:
Ok! When given points, to find the slope, you would use this equation: y2-y1/x2-x1. Let me demonstrate. In this set to find the slope with the coordinates (10,8) and (14,20), the y2 value is 20, and the y1 value is 8, and the x2 value is 14, and the y1 value is 10. So, your equation would look like this: (20-8)/(14-10), which simplifies to 12/4, or 3! So the slope is three, and that's how you do that when using an equation. OR, you could graph them, but that isn't too reliable so I do not recommend trying it, since you may not create the right slope.
Answer:
i thought i had the answer but then i got it wrong im sorry
Step-by-step explanation:
Answer:
The missing value in the ordered pair is 66
Step-by-step explanation:
Given that:
(12,10) and (-2,r)
Slope = m = -4
We have to find the value of r so that the line has a slope of -4.
Slope is the steepness of line which is denoted by m.
Here,
Putting the values in slope of line formula,
Multiplying both sides by -14
The value of r is 66
Hence,
The missing value in the ordered pair is 66
Answer:
a. The distance from the center to either vertex
Step-by-step explanation:
The distance from the center to a vertex is the fixed value <em>a</em>. The values of <em>a</em> and <em>c</em> will vary from one ellipse to another, but they are fixed for any given ellipse.
I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.
