Answer:
the correct answer is 1 92/99
Check the picture below.
so the perimeter of the kite is x+x+y+y, namely 2x + 2y.
![\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ x=\sqrt{8^2+15^2}\implies x=\sqrt{289}\implies \boxed{x=17} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7Bx%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B15%7D%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20x%3D%5Csqrt%7B8%5E2%2B15%5E2%7D%5Cimplies%20x%3D%5Csqrt%7B289%7D%5Cimplies%20%5Cboxed%7Bx%3D17%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \begin{cases} c=\stackrel{hypotenuse}{y}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{4}\\ \end{cases}\implies y=\sqrt{8^2+4^2}\implies y=\sqrt{80}\implies \boxed{y\approx 8.94} \\\\[-0.35em] ~\dotfill\\\\ 2x+2y\implies 2(17)+2(8.94)\implies 51.88\implies \stackrel{\textit{rounded up more}}{51.9}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7By%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B4%7D%5C%5C%20%5Cend%7Bcases%7D%5Cimplies%20y%3D%5Csqrt%7B8%5E2%2B4%5E2%7D%5Cimplies%20y%3D%5Csqrt%7B80%7D%5Cimplies%20%5Cboxed%7By%5Capprox%208.94%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%202x%2B2y%5Cimplies%202%2817%29%2B2%288.94%29%5Cimplies%2051.88%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%20more%7D%7D%7B51.9%7D)
Y = -1/2x + 4....sub in -1/2x + 4 in for y in the other equation
x + 2y = -8
x + 2(-1/2x + 4) = -8
x - x + 8 = -8
x - x = -8 -8
0 = -16...incorrect....NO SOLUTIONS
Answer:
(−∞, 2)∪(2, ∞)
Step-by-step explanation:
Domain is all the values that "x" can be
since finding all the values which "x" can be is too hard we will find out the values which "x" can't be- this means equating the denominator to "0" so that the function will be undetermined:

since we need the denominator to be "0" we must use the opposite of (-2) which is "2" so we will substitute "2" in the place of "x"
- the function is now "undetermined" since nothing can be divided by 0 we need to write our answer in proper domain/range format
-Hope this helps!