Answer:
y = 52500(.91)^x
Step-by-step explanation:
Exponential functions are written y = ab^x where a is the starting point and b is the common ratio. We know the initial worth is 52500 and each year the worth decreases 9% of the original year, making it work 91% of the previous value.
We know that
sin²x+cos²x=1
so
clear cos x
cos x=(+/-)√[1-sin²x]
in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5
the answer is
cos o=√21/5
Answer:
Value is x=8 and y=4
Step-by-step explanation:
Given : A right triangle 'A' hypotenuse length of x+4 and a leg of x,
and right triangle 'B' hypotenuse length of 3y and a leg length of y+4
To find : For what values of x and y are the triangles congruent by HL?
Solution :
Triangle A,
Hypotenuse: x+4
Leg: x
Triangle B,
Hypotenuse: 3y
Leg: y+4
Since the triangle A and B are congruent so, the sides of triangles are equal.
(Hypotenuse are equal) ..........[1]
and 
(Legs are equal) ..........[2]
Solving the equation of system,
Put the value of x from [2] in [1],
Substitute y in [2],
Therefore, The value of x=8 and y=4
Verifying for the values of x and y:
Triangle A,
Hypotenuse: x+4=8+4=12
Leg: x=8
Triangle B,
Hypotenuse: 3y=3(4)=12
Leg: y+4=4+4=8
Both hypotenuses and both legs are equal hence they are congruent.
Answer:
- digits used once: 12
- repeated digits: 128
Step-by-step explanation:
In order for a number to be divisible by 4, its last two digits must be divisible by 4. This will be the case if either of these conditions holds:
- the ones digit is an even multiple of 2, and the tens digit is even
- the ones digit is an odd multiple of 2, and the tens digit is odd.
We must count the ways these conditions can be met with the given digits.
__
Since we only have even numbers to work with, the ones digit must be an even multiple of 2: 4 or 8. (The tens digit cannot be odd.) The digits 4 and 8 comprise half of the available digits, so half of all possible numbers made from these digits will be divisible by 4.
<h3>digits used once</h3>
If the numbers must use each digit exactly once, there will be 4! = 24 of them. 24/2 = 12 of these 4-digit numbers will be divisible by 4.
<h3>repeated digits</h3>
Each of the four digits can have any of four values, so there will be 4^4 = 256 possible 4-digit numbers. Of these, 256/2 = 128 will be divisible by 4.
