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1 year ago

The number of students in sixth grade is 1.03 times the number of students in seventh grade. What percent is equivalent to 1.03?

Mathematics

1 answer:

Minchanka [31]1 year ago

8 0

Move the decimal to the right twice to make this into a percent:

1.03 —-> 103%

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Help on this math question ‍♀️

noname [10]

Answer:

the 2nd 3rd and 4th answers are the correct ones

Step-by-step explanation:

hope this helps you

4 0

2 years ago

Last week, Leah worked 25 hours on weekdays and 11 hours on the weekend. Which ratio compares the number of hours Leah worked on

Akimi4 [234]

Answer:

25:36

Step-by-step explanation:

the number of hours on weekdays which is 25, and the total hours she worked is 25+11 which is 36, so it is 25:36

4 0

2 years ago

A theorem is proved using a geometric proof.<br> True or False?

Lerok [7]

A theorem is defined as an existing fact that was proved to be correct through experimentation or mathematical reasoning. In this case, we can say that a theorem can be proven by geometric proof as it is required for people to consider it as a fact. Answer is true.

6 0

3 years ago

11. What is the perimeter of the garden?

Ilya [14]

Answer:

19 $\frac{1}{4}$ or 18 $\frac{5}{4}$

Step-by-step explanation:

First, add the whole numbers

3, 7, and 8

Add the fractions

$\frac{1}{2}$ + $\frac{3}{4}$ = $\frac{5}{4}$

IF YOU WANT SIMPLIFIED NUMBER DO THIS

$\frac{5}{4}$ =1 $\frac{1}{4}$

18+1 $\frac{1}{4}$ =19 $\frac{1}{4}$

6 0

2 years ago

(a) The parametric equations x = f(t) and y = g(t) give the coordinates of a point (x, y) = (f(t), g(t)) for appropriate values

Gnesinka [82]

Answer:

Step-by-step explanation:

a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.

b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).

c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

$y=t^2 = (x)^2 = x^2$

where $x\geq 0$

5 0

2 years ago